This C++ program to check whether the given number is even or odd.
even numbers are perfectly divisible by 2. In this example program, if else statement is used to check whether a number entered by the user is even or odd.
#include <iostream>
using namespace std;
int main() {
int a;
cout << "Enter the number: "; cin >> a;
/* logic */
if (a % 2 == 0) {
cout << "The given number is EVEN" << endl;
} else {
cout << "The given number is ODD" << endl;
}
return 0;
}Program Output:
Enter the number: 8 The given number is EVEN
Explanation:
Example 1: If entered number is an even number.
Let value of 'a' entered is 8
if(a%2==0) then a is an even number, else odd.
i.e. if(8%2==0) then 8 is an even number, else odd.
To check whether 8 is even or odd, we need to calculate (8%2).
/* % (modulus) implies remainder value. */
/* Therefore if the remainder obtained when 8 is divided by 2 is 0, then 8 is even. */
8%2==0 is true
Thus 8 is an even number.
Example 2: If entered number is an odd number.
Let value of 'a' entered is 7
if(a%2==0) then a is an even number, else odd.
i.e. if(7%2==0) then 4 is an even number, else odd.
To check whether 7 is even or odd, we need to calculate (7%2).
7%2==0 is false /* 7%2==1 condition fails and else part is executed */
Thus 7 is an odd number.
