Write a C program to check whether the given number is even or odd.

even numbers are perfectly *divisible by 2*. In this example, *if else* statement is used to check whether a number entered by the user is even or odd.

```
#include <stdio.h>
int main()
{
int a;
printf("Enter a: ");
scanf("%d", &a);
/* logic */ if (a % 2 == 0) {
printf("The given number is EVEN");
}
else {
printf("The given number is ODD");
}
return 0;
}
```

Enter a: 2 The given number is EVEN

Explanation:**Example 1: If entered number is an even number.**

Let value of 'a' entered is 4

if(a%2==0) then a is an even number, else odd.

i.e. if(4%2==0) then 4 is an even number, else odd.

To check whether 4 is even or odd, we need to calculate (4%2).

/* % (modulus) implies remainder value. */

/* Therefore if the remainder obtained when 4 is divided by 2 is 0, then 4 is even. */

4%2==0 is true

Thus 4 is an even number.

**Example 2: If entered number is an odd number.**

Let value of 'a' entered is 7

if(a%2==0) then a is an even number, else odd.

i.e. if(7%2==0) then 4 is an even number, else odd.

To check whether 7 is even or odd, we need to calculate (7%2).

7%2==0 is false /* 7%2==1 condition fails and else part is executed */

Thus 7 is an odd number.