C Program to Find Minimum Element in Array

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C program to find smallest element present in an array. It also prints the location or index at which minimum element occurs in array.

Program:
#include <stdio.h>

int main() 
    {    
    int array[100], minimum, size, c, location = 1;
    
    printf("Enter the number of elements in array\n");
    scanf("%d",&size);
    
    printf("Enter %d integers\n", size);
    
    for ( c = 0 ; c < size ; c++ )
    scanf("%d", &array[c]);    
    
    minimum = array[0];
    
    for ( c = 1 ; c < size ; c++ ) 
    {
        if ( array[c] < minimum ) 
        {
minimum = array[c];
location = c+1;
        }
    } 
    
    printf("Minimum element is present at location %d and it's value is %d.\n", location, minimum);
    return 0;
}
Program Output:

minimum-array-c

Same C program using pointers

Program:
#include <stdio.h>

int main() 
{
    int array[100], *minimum, size, c, location = 1;
    
    printf("Enter the number of elements in array\n");
    scanf("%d",&size);
    
    printf("Enter %d integers\n", size);
    
    for ( c = 0 ; c < size ; c++ )
    scanf("%d", &array[c]);
    
    minimum = array;
    *minimum = *array;
    
    for ( c = 1 ; c < size ; c++ ) 
    {
        if ( *(array+c) < *minimum ) 
        {
        *minimum = *(array+c);
location = c+1;
        }
    } 
    
    printf("Minimum element found at location %d and it's value is %d.\n", location, *minimum);
    return 0;
    
}

The algorithm first assumes the first element as a minimum, and then compare it with other elements if an element it is smaller than the new minimum and the entire array is scanned until the process is repeated.


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